Base | Representation |
---|---|
bin | 111011101010110010111… |
… | …100111010100011111101 |
3 | 112111222212000002201020112 |
4 | 323222302330322203331 |
5 | 1014140110141111331 |
6 | 12415410454155405 |
7 | 602146522251221 |
oct | 73526274724375 |
9 | 15458760081215 |
10 | 4100401113341 |
11 | 1340a745930a5 |
12 | 562828052b65 |
13 | 239887749440 |
14 | 102663774781 |
15 | 719da52832b |
hex | 3bab2f3a8fd |
4100401113341 has 8 divisors (see below), whose sum is σ = 4458688590720. Its totient is φ = 3748238208432.
The previous prime is 4100401113337. The next prime is 4100401113343. The reversal of 4100401113341 is 1433111040014.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4100401113341 - 22 = 4100401113337 is a prime.
It is a super-2 number, since 2×41004011133412 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4100401113343) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1531141721 + ... + 1531144398.
It is an arithmetic number, because the mean of its divisors is an integer number (557336073840).
Almost surely, 24100401113341 is an apocalyptic number.
It is an amenable number.
4100401113341 is a deficient number, since it is larger than the sum of its proper divisors (358287477379).
4100401113341 is a wasteful number, since it uses less digits than its factorization.
4100401113341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3062286235.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 4100401113341 its reverse (1433111040014), we get a palindrome (5533512153355).
The spelling of 4100401113341 in words is "four trillion, one hundred billion, four hundred one million, one hundred thirteen thousand, three hundred forty-one".
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