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4102130044113 = 31367376681371
BaseRepresentation
bin111011101100011010000…
…000010000110011010001
3112112011022111101111101120
4323230122000100303101
51014202130242402423
612420254215152453
7602240415026553
oct73543200206321
915464274344346
104102130044113
111341781516402
1256302b075729
13239aa19b50ba
1410278922b4d3
1571a8c1e3ee3
hex3bb1a010cd1

4102130044113 has 4 divisors (see below), whose sum is σ = 5469506725488. Its totient is φ = 2734753362740.

The previous prime is 4102130044097. The next prime is 4102130044139. The reversal of 4102130044113 is 3114400312014.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4102130044113 - 24 = 4102130044097 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4102130044183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 683688340683 + ... + 683688340688.

It is an arithmetic number, because the mean of its divisors is an integer number (1367376681372).

Almost surely, 24102130044113 is an apocalyptic number.

It is an amenable number.

4102130044113 is a deficient number, since it is larger than the sum of its proper divisors (1367376681375).

4102130044113 is a wasteful number, since it uses less digits than its factorization.

4102130044113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1367376681374.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 4102130044113 its reverse (3114400312014), we get a palindrome (7216530356127).

The spelling of 4102130044113 in words is "four trillion, one hundred two billion, one hundred thirty million, forty-four thousand, one hundred thirteen".

Divisors: 1 3 1367376681371 4102130044113