Base | Representation |
---|---|
bin | 111011101100011010000… |
… | …000010000110011010001 |
3 | 112112011022111101111101120 |
4 | 323230122000100303101 |
5 | 1014202130242402423 |
6 | 12420254215152453 |
7 | 602240415026553 |
oct | 73543200206321 |
9 | 15464274344346 |
10 | 4102130044113 |
11 | 1341781516402 |
12 | 56302b075729 |
13 | 239aa19b50ba |
14 | 10278922b4d3 |
15 | 71a8c1e3ee3 |
hex | 3bb1a010cd1 |
4102130044113 has 4 divisors (see below), whose sum is σ = 5469506725488. Its totient is φ = 2734753362740.
The previous prime is 4102130044097. The next prime is 4102130044139. The reversal of 4102130044113 is 3114400312014.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4102130044113 - 24 = 4102130044097 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4102130044183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 683688340683 + ... + 683688340688.
It is an arithmetic number, because the mean of its divisors is an integer number (1367376681372).
Almost surely, 24102130044113 is an apocalyptic number.
It is an amenable number.
4102130044113 is a deficient number, since it is larger than the sum of its proper divisors (1367376681375).
4102130044113 is a wasteful number, since it uses less digits than its factorization.
4102130044113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1367376681374.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 4102130044113 its reverse (3114400312014), we get a palindrome (7216530356127).
The spelling of 4102130044113 in words is "four trillion, one hundred two billion, one hundred thirty million, forty-four thousand, one hundred thirteen".
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