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41023433131 = 86694732199
BaseRepresentation
bin100110001101001011…
…111110100110101011
310220212222211022211021
4212031023332212223
51133003444330011
630502414313311
72651412266602
oct461513764653
9126788738737
1041023433131
111644172754a
127b4a7b8837
133b3a1056b5
141db2498a39
151101796471
hex98d2fe9ab

41023433131 has 4 divisors (see below), whose sum is σ = 41028174000. Its totient is φ = 41018692264.

The previous prime is 41023433111. The next prime is 41023433153. The reversal of 41023433131 is 13133432014.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41023433131 is a prime.

It is a super-2 number, since 2×410234331312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41023433096 and 41023433105.

It is not an unprimeable number, because it can be changed into a prime (41023433111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2357431 + ... + 2374768.

It is an arithmetic number, because the mean of its divisors is an integer number (10257043500).

Almost surely, 241023433131 is an apocalyptic number.

41023433131 is a deficient number, since it is larger than the sum of its proper divisors (4740869).

41023433131 is an equidigital number, since it uses as much as digits as its factorization.

41023433131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4740868.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 41023433131 its reverse (13133432014), we get a palindrome (54156865145).

The spelling of 41023433131 in words is "forty-one billion, twenty-three million, four hundred thirty-three thousand, one hundred thirty-one".

Divisors: 1 8669 4732199 41023433131