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41055401341 = 197320808617
BaseRepresentation
bin100110001111000101…
…111011010101111101
310220222012222110222001
4212033011323111331
51133040140320331
630505515422301
72652251103433
oct461705732575
9126865873861
1041055401341
1116458781759
127b59454991
133b439194b6
141db681ad53
1511044ad561
hex98f17b57d

41055401341 has 4 divisors (see below), whose sum is σ = 41076211932. Its totient is φ = 41034590752.

The previous prime is 41055401293. The next prime is 41055401357. The reversal of 41055401341 is 14310455014.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 20205485316 + 20849916025 = 142146^2 + 144395^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41055401341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41055401141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10402336 + ... + 10406281.

It is an arithmetic number, because the mean of its divisors is an integer number (10269052983).

Almost surely, 241055401341 is an apocalyptic number.

It is an amenable number.

41055401341 is a deficient number, since it is larger than the sum of its proper divisors (20810591).

41055401341 is a wasteful number, since it uses less digits than its factorization.

41055401341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20810590.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 41055401341 its reverse (14310455014), we get a palindrome (55365856355).

The spelling of 41055401341 in words is "forty-one billion, fifty-five million, four hundred one thousand, three hundred forty-one".

Divisors: 1 1973 20808617 41055401341