Base | Representation |
---|---|
bin | 1011111101100011100… |
… | …00010110011011000111 |
3 | 1110021212120210100112111 |
4 | 11332301300112123013 |
5 | 23213214024310421 |
6 | 512451313001451 |
7 | 41460031335403 |
oct | 5766160263307 |
9 | 1407776710474 |
10 | 411004135111 |
11 | 149340134a39 |
12 | 677a4553287 |
13 | 2c9b0382bab |
14 | 15c6d82c103 |
15 | aa57a02ee1 |
hex | 5fb1c166c7 |
411004135111 has 4 divisors (see below), whose sum is σ = 411060069000. Its totient is φ = 410948201224.
The previous prime is 411004135051. The next prime is 411004135123. The reversal of 411004135111 is 111531400114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 411004135111 - 29 = 411004134599 is a prime.
It is a super-2 number, since 2×4110041351112 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (411004135181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27955921 + ... + 27970618.
It is an arithmetic number, because the mean of its divisors is an integer number (102765017250).
Almost surely, 2411004135111 is an apocalyptic number.
411004135111 is a deficient number, since it is larger than the sum of its proper divisors (55933889).
411004135111 is an equidigital number, since it uses as much as digits as its factorization.
411004135111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55933888.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 411004135111 its reverse (111531400114), we get a palindrome (522535535225).
The spelling of 411004135111 in words is "four hundred eleven billion, four million, one hundred thirty-five thousand, one hundred eleven".
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