Base | Representation |
---|---|
bin | 111011110011110101101… |
… | …110110010111011011011 |
3 | 112112220220201202101222110 |
4 | 323303311232302323123 |
5 | 1014320002010420443 |
6 | 12424054211523403 |
7 | 602642251431432 |
oct | 73636556627333 |
9 | 15486821671873 |
10 | 4110111420123 |
11 | 13450a7823325 |
12 | 564697bb9563 |
13 | 23a7744071b7 |
14 | 102d05248119 |
15 | 71da7c61233 |
hex | 3bcf5bb2edb |
4110111420123 has 64 divisors (see below), whose sum is σ = 5776120627200. Its totient is φ = 2597127287040.
The previous prime is 4110111420061. The next prime is 4110111420127. The reversal of 4110111420123 is 3210241110114.
It is not a de Polignac number, because 4110111420123 - 29 = 4110111419611 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4110111420123.
It is not an unprimeable number, because it can be changed into a prime (4110111420127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 692051488 + ... + 692057426.
It is an arithmetic number, because the mean of its divisors is an integer number (90251884800).
Almost surely, 24110111420123 is an apocalyptic number.
4110111420123 is a deficient number, since it is larger than the sum of its proper divisors (1666009207077).
4110111420123 is a wasteful number, since it uses less digits than its factorization.
4110111420123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7192.
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 4110111420123 its reverse (3210241110114), we get a palindrome (7320352530237).
The spelling of 4110111420123 in words is "four trillion, one hundred ten billion, one hundred eleven million, four hundred twenty thousand, one hundred twenty-three".
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