41101312003 has 4 divisors (see below), whose sum is σ = 41151012120. Its totient is φ = 41051611888.

The previous prime is 41101311989. The next prime is 41101312019. The reversal of 41101312003 is 30021310114.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30021310114 = 2 ⋅15010655057.

It is a cyclic number.

It is not a de Polignac number, because 41101312003 - 2⁵ = 41101311971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41101312093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24848818 + ... + 24850471.

It is an arithmetic number, because the mean of its divisors is an integer number (10287753030).

Almost surely, 2^41101312003 is an apocalyptic number.

41101312003 is a deficient number, since it is larger than the sum of its proper divisors (49700117).

41101312003 is an equidigital number, since it uses as much as digits as its factorization.

41101312003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49700116.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 41101312003 its reverse (30021310114), we get a palindrome (71122622117).

The spelling of 41101312003 in words is "forty-one billion, one hundred one million, three hundred twelve thousand, three".