Base | Representation |
---|---|
bin | 101110101110100001010100… |
… | …0101110000101101101011001 |
3 | 1222220021120000210221000111120 |
4 | 1131131002220232011231121 |
5 | 412333023203334343223 |
6 | 4014053122401315453 |
7 | 152400532411560615 |
oct | 13535025056055531 |
9 | 1886246023830446 |
10 | 411014021012313 |
11 | 109a64081825694 |
12 | 3a121330035b89 |
13 | 148455c0729aa4 |
14 | 736d282da6345 |
15 | 327b6406bbbe3 |
hex | 175d0a8b85b59 |
411014021012313 has 4 divisors (see below), whose sum is σ = 548018694683088. Its totient is φ = 274009347341540.
The previous prime is 411014021012303. The next prime is 411014021012401. The reversal of 411014021012313 is 313210120410114.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 411014021012313 - 25 = 411014021012281 is a prime.
It is not an unprimeable number, because it can be changed into a prime (411014021012303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68502336835383 + ... + 68502336835388.
It is an arithmetic number, because the mean of its divisors is an integer number (137004673670772).
Almost surely, 2411014021012313 is an apocalyptic number.
It is an amenable number.
411014021012313 is a deficient number, since it is larger than the sum of its proper divisors (137004673670775).
411014021012313 is a wasteful number, since it uses less digits than its factorization.
411014021012313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 137004673670774.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 411014021012313 its reverse (313210120410114), we get a palindrome (724224141422427).
The spelling of 411014021012313 in words is "four hundred eleven trillion, fourteen billion, twenty-one million, twelve thousand, three hundred thirteen".
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