41101450103533 has 4 divisors (see below), whose sum is σ = 41112889419708. Its totient is φ = 41090010787360.

The previous prime is 41101450103509. The next prime is 41101450103551. The reversal of 41101450103533 is 33530105410114.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 24536696623209 + 16564753480324 = 4953453^2 + 4069982^2 .

It is a cyclic number.

It is not a de Polignac number, because 41101450103533 - 2²⁵ = 41101416549101 is a prime.

It is a super-2 number, since 2×41101450103533² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41101450103495 and 41101450103504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41101450203533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5719652698 + ... + 5719659883.

It is an arithmetic number, because the mean of its divisors is an integer number (10278222354927).

Almost surely, 2^{41101450103533} is an apocalyptic number.

It is an amenable number.

41101450103533 is a deficient number, since it is larger than the sum of its proper divisors (11439316175).

41101450103533 is a wasteful number, since it uses less digits than its factorization.

41101450103533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11439316174.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 41101450103533 its reverse (33530105410114), we get a palindrome (74631555513647).

The spelling of 41101450103533 in words is "forty-one trillion, one hundred one billion, four hundred fifty million, one hundred three thousand, five hundred thirty-three".