411030040301 has 4 divisors (see below), whose sum is σ = 411039420192. Its totient is φ = 411020660412.

The previous prime is 411030040283. The next prime is 411030040331. The reversal of 411030040301 is 103040030114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-411030040301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 411030040301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411030040331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4623905 + ... + 4711958.

It is an arithmetic number, because the mean of its divisors is an integer number (102759855048).

Almost surely, 2^411030040301 is an apocalyptic number.

It is an amenable number.

411030040301 is a deficient number, since it is larger than the sum of its proper divisors (9379891).

411030040301 is an equidigital number, since it uses as much as digits as its factorization.

411030040301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9379890.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 411030040301 its reverse (103040030114), we get a palindrome (514070070415).

The spelling of 411030040301 in words is "four hundred eleven billion, thirty million, forty thousand, three hundred one".