41103013431 has 4 divisors (see below), whose sum is σ = 54804017912. Its totient is φ = 27402008952.

The previous prime is 41103013403. The next prime is 41103013433. The reversal of 41103013431 is 13431030114.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 41103013431 - 2¹⁰ = 41103012407 is a prime.

It is a super-2 number, since 2×41103013431² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41103013398 and 41103013407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41103013433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6850502236 + ... + 6850502241.

It is an arithmetic number, because the mean of its divisors is an integer number (13701004478).

Almost surely, 2^41103013431 is an apocalyptic number.

41103013431 is a deficient number, since it is larger than the sum of its proper divisors (13701004481).

41103013431 is a wasteful number, since it uses less digits than its factorization.

41103013431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13701004480.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 41103013431 its reverse (13431030114), we get a palindrome (54534043545).

The spelling of 41103013431 in words is "forty-one billion, one hundred three million, thirteen thousand, four hundred thirty-one".