Base | Representation |
---|---|
bin | 111011110100101011010… |
… | …011000100000110110001 |
3 | 112120000020100211002121021 |
4 | 323310223103010012301 |
5 | 1014323322042320423 |
6 | 12424323314055441 |
7 | 603003443314141 |
oct | 73645323040661 |
9 | 15500210732537 |
10 | 4111010120113 |
11 | 1345519047996 |
12 | 5648a8b7a581 |
13 | 23a888666c40 |
14 | 102d8c746921 |
15 | 71e0bad295d |
hex | 3bd2b4c41b1 |
4111010120113 has 16 divisors (see below), whose sum is σ = 4480728215040. Its totient is φ = 3748935947904.
The previous prime is 4111010120099. The next prime is 4111010120117. The reversal of 4111010120113 is 3110210101114.
4111010120113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4111010120113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4111010120117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 58834245 + ... + 58904077.
It is an arithmetic number, because the mean of its divisors is an integer number (280045513440).
Almost surely, 24111010120113 is an apocalyptic number.
It is an amenable number.
4111010120113 is a deficient number, since it is larger than the sum of its proper divisors (369718094927).
4111010120113 is a wasteful number, since it uses less digits than its factorization.
4111010120113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 124488.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 4111010120113 its reverse (3110210101114), we get a palindrome (7221220221227).
The spelling of 4111010120113 in words is "four trillion, one hundred eleven billion, ten million, one hundred twenty thousand, one hundred thirteen".
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