Base | Representation |
---|---|
bin | 100110010010010110… |
… | …101000100010110001 |
3 | 10221010000221002110210 |
4 | 212102112220202301 |
5 | 1133143142044213 |
6 | 30515152214333 |
7 | 2653514122125 |
oct | 462226504261 |
9 | 127100832423 |
10 | 41110112433 |
11 | 1648664aa35 |
12 | 7b7383a3a9 |
13 | 3b52064020 |
14 | 1dbdbbd585 |
15 | 11091b90c3 |
hex | 9925a88b1 |
41110112433 has 32 divisors (see below), whose sum is σ = 59406721920. Its totient is φ = 25137285120.
The previous prime is 41110112431. The next prime is 41110112437. The reversal of 41110112433 is 33421101114.
It is not a de Polignac number, because 41110112433 - 21 = 41110112431 is a prime.
It is a super-3 number, since 3×411101124333 (a number of 33 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (41110112431) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13332910 + ... + 13335992.
It is an arithmetic number, because the mean of its divisors is an integer number (1856460060).
Almost surely, 241110112433 is an apocalyptic number.
It is an amenable number.
41110112433 is a deficient number, since it is larger than the sum of its proper divisors (18296609487).
41110112433 is a wasteful number, since it uses less digits than its factorization.
41110112433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5169.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 41110112433 its reverse (33421101114), we get a palindrome (74531213547).
The spelling of 41110112433 in words is "forty-one billion, one hundred ten million, one hundred twelve thousand, four hundred thirty-three".
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