Base | Representation |
---|---|
bin | 100110010010100010… |
… | …011100110010011111 |
3 | 10221010020202110120001 |
4 | 212102202130302133 |
5 | 1133144440210030 |
6 | 30515342435131 |
7 | 2653552343023 |
oct | 462242346237 |
9 | 127106673501 |
10 | 41113210015 |
11 | 16488376219 |
12 | 7b74892aa7 |
13 | 3b528a9c07 |
14 | 1dc0388383 |
15 | 11095cbcca |
hex | 99289cc9f |
41113210015 has 4 divisors (see below), whose sum is σ = 49335852024. Its totient is φ = 32890568008.
The previous prime is 41113210007. The next prime is 41113210157. The reversal of 41113210015 is 51001231114.
41113210015 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41113210015 - 23 = 41113210007 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 41113209974 and 41113210001.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4111320997 + ... + 4111321006.
It is an arithmetic number, because the mean of its divisors is an integer number (12333963006).
Almost surely, 241113210015 is an apocalyptic number.
41113210015 is a deficient number, since it is larger than the sum of its proper divisors (8222642009).
41113210015 is an equidigital number, since it uses as much as digits as its factorization.
41113210015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8222642008.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 41113210015 its reverse (51001231114), we get a palindrome (92114441129).
The spelling of 41113210015 in words is "forty-one billion, one hundred thirteen million, two hundred ten thousand, fifteen".
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