Base | Representation |
---|---|
bin | 1011111101110010111… |
… | …01000100110100010111 |
3 | 1110022012120211121102221 |
4 | 11332321131010310113 |
5 | 23214000111044431 |
6 | 512512205243211 |
7 | 41463160250401 |
oct | 5767135046427 |
9 | 1408176747387 |
10 | 411133299991 |
11 | 1493a7036477 |
12 | 6781b863507 |
13 | 2ca0106850b |
14 | 15c82a51b71 |
15 | aa64019111 |
hex | 5fb9744d17 |
411133299991 has 4 divisors (see below), whose sum is σ = 411194098312. Its totient is φ = 411072501672.
The previous prime is 411133299979. The next prime is 411133300031. The reversal of 411133299991 is 199992331114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 411133299991 - 25 = 411133299959 is a prime.
It is a super-2 number, since 2×4111332999912 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (411133299191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30389016 + ... + 30402541.
It is an arithmetic number, because the mean of its divisors is an integer number (102798524578).
Almost surely, 2411133299991 is an apocalyptic number.
411133299991 is a deficient number, since it is larger than the sum of its proper divisors (60798321).
411133299991 is an equidigital number, since it uses as much as digits as its factorization.
411133299991 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60798320.
The product of its digits is 472392, while the sum is 52.
The spelling of 411133299991 in words is "four hundred eleven billion, one hundred thirty-three million, two hundred ninety-nine thousand, nine hundred ninety-one".
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