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411144214303 = 1033991691401
BaseRepresentation
bin1011111101110100001…
…10101101011100011111
31110022020100101010001201
411332322012231130133
523214010404324203
6512513235220331
741463352105504
oct5767206553437
91408210333051
10411144214303
11149402210569
12678234476a7
132ca033ba2a4
1415c842934ab
15aa64e72e1d
hex5fba1ad71f

411144214303 has 4 divisors (see below), whose sum is σ = 415135905808. Its totient is φ = 407152522800.

The previous prime is 411144214291. The next prime is 411144214319. The reversal of 411144214303 is 303412441114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-411144214303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411144214373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1995845598 + ... + 1995845803.

It is an arithmetic number, because the mean of its divisors is an integer number (103783976452).

Almost surely, 2411144214303 is an apocalyptic number.

411144214303 is a deficient number, since it is larger than the sum of its proper divisors (3991691505).

411144214303 is a wasteful number, since it uses less digits than its factorization.

411144214303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3991691504.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 411144214303 its reverse (303412441114), we get a palindrome (714556655417).

The spelling of 411144214303 in words is "four hundred eleven billion, one hundred forty-four million, two hundred fourteen thousand, three hundred three".

Divisors: 1 103 3991691401 411144214303