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41120113 = 231787831
BaseRepresentation
bin1001110011011…
…1000101110001
32212101010012011
42130313011301
541011320423
64025202521
71006341466
oct234670561
985333164
1041120113
1121236171
1211930441
138699638
14566566d
153923b0d
hex2737171

41120113 has 4 divisors (see below), whose sum is σ = 42907968. Its totient is φ = 39332260.

The previous prime is 41120099. The next prime is 41120117. The reversal of 41120113 is 31102114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41120113 - 25 = 41120081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41120093 and 41120102.

It is not an unprimeable number, because it can be changed into a prime (41120117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 893893 + ... + 893938.

It is an arithmetic number, because the mean of its divisors is an integer number (10726992).

Almost surely, 241120113 is an apocalyptic number.

It is an amenable number.

41120113 is a deficient number, since it is larger than the sum of its proper divisors (1787855).

41120113 is a wasteful number, since it uses less digits than its factorization.

41120113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1787854.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 41120113 is about 6412.4966276794. The cubic root of 41120113 is about 345.1581239732.

Adding to 41120113 its reverse (31102114), we get a palindrome (72222227).

The spelling of 41120113 in words is "forty-one million, one hundred twenty thousand, one hundred thirteen".

Divisors: 1 23 1787831 41120113