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41120303114234 = 220560151557117
BaseRepresentation
bin10010101100110000100010…
…00011110110011111111010
312101121001200121212211212002
421112120101003312133322
520342203340044123414
6223242223444021002
711442562305305111
oct1126302103663772
9171531617784762
1041120303114234
1112114028116313
124741482391762
1319c3821798aa6
14a2233a20cc78
154b4977d604de
hex2566110f67fa

41120303114234 has 4 divisors (see below), whose sum is σ = 61680454671354. Its totient is φ = 20560151557116.

The previous prime is 41120303114197. The next prime is 41120303114263. The reversal of 41120303114234 is 43241130302114.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 36728751180625 + 4391551933609 = 6060425^2 + 2095603^2 .

It is a junction number, because it is equal to n+sod(n) for n = 41120303114197 and 41120303114206.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10280075778557 + ... + 10280075778560.

Almost surely, 241120303114234 is an apocalyptic number.

41120303114234 is a deficient number, since it is larger than the sum of its proper divisors (20560151557120).

41120303114234 is a wasteful number, since it uses less digits than its factorization.

41120303114234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20560151557119.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 41120303114234 its reverse (43241130302114), we get a palindrome (84361433416348).

The spelling of 41120303114234 in words is "forty-one trillion, one hundred twenty billion, three hundred three million, one hundred fourteen thousand, two hundred thirty-four".

Divisors: 1 2 20560151557117 41120303114234