41121341233 has 8 divisors (see below), whose sum is σ = 47004133568. Its totient is φ = 35240627664.

The previous prime is 41121341201. The next prime is 41121341243. The reversal of 41121341233 is 33214312114.

41121341233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 41121341233 - 2⁵ = 41121341201 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41121341198 and 41121341207.

It is not an unprimeable number, because it can be changed into a prime (41121341243) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 477066 + ... + 556627.

It is an arithmetic number, because the mean of its divisors is an integer number (5875516696).

Almost surely, 2^41121341233 is an apocalyptic number.

It is an amenable number.

41121341233 is a deficient number, since it is larger than the sum of its proper divisors (5882792335).

41121341233 is a wasteful number, since it uses less digits than its factorization.

41121341233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1039383.

The product of its digits is 1728, while the sum is 25.

Adding to 41121341233 its reverse (33214312114), we get a palindrome (74335653347).

The spelling of 41121341233 in words is "forty-one billion, one hundred twenty-one million, three hundred forty-one thousand, two hundred thirty-three".