41122411320041 has 4 divisors (see below), whose sum is σ = 41997356241792. Its totient is φ = 40247466398292.

The previous prime is 41122411319999. The next prime is 41122411320059. The reversal of 41122411320041 is 14002311422114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41122411320041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41122411320541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437472460805 + ... + 437472460898.

It is an arithmetic number, because the mean of its divisors is an integer number (10499339060448).

Almost surely, 2^{41122411320041} is an apocalyptic number.

It is an amenable number.

41122411320041 is a deficient number, since it is larger than the sum of its proper divisors (874944921751).

41122411320041 is an equidigital number, since it uses as much as digits as its factorization.

41122411320041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 874944921750.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 41122411320041 its reverse (14002311422114), we get a palindrome (55124722742155).

The spelling of 41122411320041 in words is "forty-one trillion, one hundred twenty-two billion, four hundred eleven million, three hundred twenty thousand, forty-one".