4112242413003 has 6 divisors (see below), whose sum is σ = 5939905707684. Its totient is φ = 2741494941996.

The previous prime is 4112242412987. The next prime is 4112242413017. The reversal of 4112242413003 is 3003142422114.

4112242413003 is a `hidden beast` number, since 4 + 1 + 1 + 2 + 242 + 413 + 0 + 0 + 3 = 666.

It is not a de Polignac number, because 4112242413003 - 2⁴ = 4112242412987 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4112242413053) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 228457911825 + ... + 228457911842.

It is an arithmetic number, because the mean of its divisors is an integer number (989984284614).

Almost surely, 2^{4112242413003} is an apocalyptic number.

4112242413003 is a deficient number, since it is larger than the sum of its proper divisors (1827663294681).

4112242413003 is a wasteful number, since it uses less digits than its factorization.

4112242413003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 456915823673 (or 456915823670 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 4112242413003 its reverse (3003142422114), we get a palindrome (7115384835117).

The spelling of 4112242413003 in words is "four trillion, one hundred twelve billion, two hundred forty-two million, four hundred thirteen thousand, three".