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4112242413017 is a prime number
BaseRepresentation
bin111011110101110100101…
…111111000110111011001
3112120010102020121001200012
4323311310233320313121
51014333333024204032
612425045454251305
7603046125530624
oct73656457706731
915503366531605
104112242413017
111345aa06aa882
12564b917b6b35
1323aa23a56c3b
14103068280dbb
1571e7ed9b6b2
hex3bd74bf8dd9

4112242413017 has 2 divisors, whose sum is σ = 4112242413018. Its totient is φ = 4112242413016.

The previous prime is 4112242412987. The next prime is 4112242413029. The reversal of 4112242413017 is 7103142422114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3927012025561 + 185230387456 = 1981669^2 + 430384^2 .

It is a cyclic number.

It is not a de Polignac number, because 4112242413017 - 224 = 4112225635801 is a prime.

It is a super-3 number, since 3×41122424130173 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (4112242412017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056121206508 + 2056121206509.

It is an arithmetic number, because the mean of its divisors is an integer number (2056121206509).

Almost surely, 24112242413017 is an apocalyptic number.

It is an amenable number.

4112242413017 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112242413017 is an equidigital number, since it uses as much as digits as its factorization.

4112242413017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10752, while the sum is 32.

The spelling of 4112242413017 in words is "four trillion, one hundred twelve billion, two hundred forty-two million, four hundred thirteen thousand, seventeen".