Base | Representation |
---|---|
bin | 111011110101110100110… |
… | …011010011111100000101 |
3 | 112120010102022021122120102 |
4 | 323311310303103330011 |
5 | 1014333333241412331 |
6 | 12425045525413445 |
7 | 603046136256005 |
oct | 73656463237405 |
9 | 15503368248512 |
10 | 4112243310341 |
11 | 1345aa1162a71 |
12 | 564b91b6a285 |
13 | 23aa23cac4ba |
14 | 103068436005 |
15 | 71e7eec74cb |
hex | 3bd74cd3f05 |
4112243310341 has 16 divisors (see below), whose sum is σ = 4469273149440. Its totient is φ = 3769327139760.
The previous prime is 4112243310289. The next prime is 4112243310347. The reversal of 4112243310341 is 1430133422114.
It is a cyclic number.
It is not a de Polignac number, because 4112243310341 - 26 = 4112243310277 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4112243310347) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1997876 + ... + 3495138.
It is an arithmetic number, because the mean of its divisors is an integer number (279329571840).
Almost surely, 24112243310341 is an apocalyptic number.
It is an amenable number.
4112243310341 is a deficient number, since it is larger than the sum of its proper divisors (357029839099).
4112243310341 is a wasteful number, since it uses less digits than its factorization.
4112243310341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1501976.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 4112243310341 its reverse (1430133422114), we get a palindrome (5542376732455).
The spelling of 4112243310341 in words is "four trillion, one hundred twelve billion, two hundred forty-three million, three hundred ten thousand, three hundred forty-one".
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