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4112243310341 = 193146631497263
BaseRepresentation
bin111011110101110100110…
…011010011111100000101
3112120010102022021122120102
4323311310303103330011
51014333333241412331
612425045525413445
7603046136256005
oct73656463237405
915503368248512
104112243310341
111345aa1162a71
12564b91b6a285
1323aa23cac4ba
14103068436005
1571e7eec74cb
hex3bd74cd3f05

4112243310341 has 16 divisors (see below), whose sum is σ = 4469273149440. Its totient is φ = 3769327139760.

The previous prime is 4112243310289. The next prime is 4112243310347. The reversal of 4112243310341 is 1430133422114.

It is a cyclic number.

It is not a de Polignac number, because 4112243310341 - 26 = 4112243310277 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4112243310347) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1997876 + ... + 3495138.

It is an arithmetic number, because the mean of its divisors is an integer number (279329571840).

Almost surely, 24112243310341 is an apocalyptic number.

It is an amenable number.

4112243310341 is a deficient number, since it is larger than the sum of its proper divisors (357029839099).

4112243310341 is a wasteful number, since it uses less digits than its factorization.

4112243310341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1501976.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4112243310341 its reverse (1430133422114), we get a palindrome (5542376732455).

The spelling of 4112243310341 in words is "four trillion, one hundred twelve billion, two hundred forty-three million, three hundred ten thousand, three hundred forty-one".

Divisors: 1 19 31 589 4663 88597 144553 1497263 2746507 28447997 46415153 881887907 6981737369 132653010011 216433858439 4112243310341