Base | Representation |
---|---|
bin | 100110010011001000… |
… | …000000001001000111 |
3 | 10221010221021121011200 |
4 | 212103020000021013 |
5 | 1133210000213101 |
6 | 30520333433543 |
7 | 2654032123104 |
oct | 462310001107 |
9 | 127127247150 |
10 | 41123054151 |
11 | 1649298a273 |
12 | 7b7803b8b3 |
13 | 3b5494584a |
14 | 1dc17cbaab |
15 | 110a3c3986 |
hex | 993200247 |
41123054151 has 6 divisors (see below), whose sum is σ = 59399967120. Its totient is φ = 27415369428.
The previous prime is 41123054113. The next prime is 41123054233. The reversal of 41123054151 is 15145032114.
41123054151 is a `hidden beast` number, since 4 + 11 + 230 + 5 + 415 + 1 = 666.
It is not a de Polignac number, because 41123054151 - 29 = 41123053639 is a prime.
It is a super-2 number, since 2×411230541512 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41123054551) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2284614111 + ... + 2284614128.
It is an arithmetic number, because the mean of its divisors is an integer number (9899994520).
Almost surely, 241123054151 is an apocalyptic number.
41123054151 is a deficient number, since it is larger than the sum of its proper divisors (18276912969).
41123054151 is a wasteful number, since it uses less digits than its factorization.
41123054151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4569228245 (or 4569228242 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 41123054151 its reverse (15145032114), we get a palindrome (56268086265).
The spelling of 41123054151 in words is "forty-one billion, one hundred twenty-three million, fifty-four thousand, one hundred fifty-one".
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