4112412203131 has 4 divisors (see below), whose sum is σ = 4112942365872. Its totient is φ = 4111882040392.

The previous prime is 4112412203129. The next prime is 4112412203219. The reversal of 4112412203131 is 1313022142114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4112412203131 - 2¹ = 4112412203129 is a prime.

It is a super-2 number, since 2×4112412203131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4112412203096 and 4112412203105.

It is not an unprimeable number, because it can be changed into a prime (4112412243131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 265069735 + ... + 265085248.

It is an arithmetic number, because the mean of its divisors is an integer number (1028235591468).

Almost surely, 2^{4112412203131} is an apocalyptic number.

4112412203131 is a deficient number, since it is larger than the sum of its proper divisors (530162741).

4112412203131 is an equidigital number, since it uses as much as digits as its factorization.

4112412203131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 530162740.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 4112412203131 its reverse (1313022142114), we get a palindrome (5425434345245).

The spelling of 4112412203131 in words is "four trillion, one hundred twelve billion, four hundred twelve million, two hundred three thousand, one hundred thirty-one".