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4112433055 = 51943288769
BaseRepresentation
bin1111010100011110…
…1011111110011111
3101121121021020121101
43311013223332133
531410240324210
61520023413531
7203624050513
oct36507537637
911547236541
104112433055
1118203a7905
129692b42a7
13506cc9353
142b0260143
15191083a3a
hexf51ebf9f

4112433055 has 8 divisors (see below), whose sum is σ = 5194652400. Its totient is φ = 3116791296.

The previous prime is 4112433047. The next prime is 4112433071. The reversal of 4112433055 is 5503342114.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4112433055 - 23 = 4112433047 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21644290 + ... + 21644479.

It is an arithmetic number, because the mean of its divisors is an integer number (649331550).

Almost surely, 24112433055 is an apocalyptic number.

4112433055 is a deficient number, since it is larger than the sum of its proper divisors (1082219345).

4112433055 is a wasteful number, since it uses less digits than its factorization.

4112433055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43288793.

The product of its (nonzero) digits is 7200, while the sum is 28.

The square root of 4112433055 is about 64128.2547322161. The cubic root of 4112433055 is about 1602.1368655611.

Adding to 4112433055 its reverse (5503342114), we get a palindrome (9615775169).

The spelling of 4112433055 in words is "four billion, one hundred twelve million, four hundred thirty-three thousand, fifty-five".

Divisors: 1 5 19 95 43288769 216443845 822486611 4112433055