411247841 has 4 divisors (see below), whose sum is σ = 413867412. Its totient is φ = 408628272.

The previous prime is 411247831. The next prime is 411247847. The reversal of 411247841 is 148742114.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 118701025 + 292546816 = 10895^2 + 17104^2 .

It is a cyclic number.

It is not a de Polignac number, because 411247841 - 2⁶ = 411247777 is a prime.

It is a super-2 number, since 2×411247841² = 338249573454322562, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411247798 and 411247807.

It is not an unprimeable number, because it can be changed into a prime (411247847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1309550 + ... + 1309863.

It is an arithmetic number, because the mean of its divisors is an integer number (103466853).

Almost surely, 2^411247841 is an apocalyptic number.

It is an amenable number.

411247841 is a deficient number, since it is larger than the sum of its proper divisors (2619571).

411247841 is a wasteful number, since it uses less digits than its factorization.

411247841 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2619570.

The product of its digits is 7168, while the sum is 32.

The square root of 411247841 is about 20279.2465589824. The cubic root of 411247841 is about 743.6487923298.

Adding to 411247841 its reverse (148742114), we get a palindrome (559989955).

The spelling of 411247841 in words is "four hundred eleven million, two hundred forty-seven thousand, eight hundred forty-one".