411252434061341 has 4 divisors (see below), whose sum is σ = 411252508855872. Its totient is φ = 411252359266812.

The previous prime is 411252434061331. The next prime is 411252434061379. The reversal of 411252434061341 is 143160434252114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411252434061341 - 2⁶ = 411252434061277 is a prime.

It is a super-2 number, since 2×411252434061341² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411252434061331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28433435 + ... + 40385208.

It is an arithmetic number, because the mean of its divisors is an integer number (102813127213968).

Almost surely, 2^{411252434061341} is an apocalyptic number.

It is an amenable number.

411252434061341 is a deficient number, since it is larger than the sum of its proper divisors (74794531).

411252434061341 is an equidigital number, since it uses as much as digits as its factorization.

411252434061341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74794530.

The product of its (nonzero) digits is 276480, while the sum is 41.

The spelling of 411252434061341 in words is "four hundred eleven trillion, two hundred fifty-two billion, four hundred thirty-four million, sixty-one thousand, three hundred forty-one".