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41125332543 = 313708444181
BaseRepresentation
bin100110010011010000…
…101100011000111111
310221011002120100112120
4212103100230120333
51133211041120133
630520454334023
72654060362461
oct462320543077
9127132510476
1041125332543
11164941a6039
127b7895a313
133b552628c9
141dc1c22131
15110a6c3ab3
hex99342c63f

41125332543 has 4 divisors (see below), whose sum is σ = 54833776728. Its totient is φ = 27416888360.

The previous prime is 41125332541. The next prime is 41125332557. The reversal of 41125332543 is 34523352114.

41125332543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41125332543 - 21 = 41125332541 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41125332541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6854222088 + ... + 6854222093.

It is an arithmetic number, because the mean of its divisors is an integer number (13708444182).

Almost surely, 241125332543 is an apocalyptic number.

41125332543 is a deficient number, since it is larger than the sum of its proper divisors (13708444185).

41125332543 is a wasteful number, since it uses less digits than its factorization.

41125332543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13708444184.

The product of its digits is 43200, while the sum is 33.

Adding to 41125332543 its reverse (34523352114), we get a palindrome (75648684657).

The spelling of 41125332543 in words is "forty-one billion, one hundred twenty-five million, three hundred thirty-two thousand, five hundred forty-three".

Divisors: 1 3 13708444181 41125332543