4113011333401 has 4 divisors (see below), whose sum is σ = 4113019411072. Its totient is φ = 4113003255732.

The previous prime is 4113011333393. The next prime is 4113011333411. The reversal of 4113011333401 is 1043331103114.

4113011333401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4113011333401 - 2³ = 4113011333393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4113011333411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3219681 + ... + 4311886.

It is an arithmetic number, because the mean of its divisors is an integer number (1028254852768).

Almost surely, 2^{4113011333401} is an apocalyptic number.

It is an amenable number.

4113011333401 is a deficient number, since it is larger than the sum of its proper divisors (8077671).

4113011333401 is an equidigital number, since it uses as much as digits as its factorization.

4113011333401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8077670.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 4113011333401 its reverse (1043331103114), we get a palindrome (5156342436515).

The spelling of 4113011333401 in words is "four trillion, one hundred thirteen billion, eleven million, three hundred thirty-three thousand, four hundred one".