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4113015303 = 33171622901
BaseRepresentation
bin1111010100100111…
…1010001000000111
3101121122100211022010
43311021322020013
531410412442203
61520044105303
7203632024155
oct36511721007
911548324263
104113015303
111820765301
12969535233
13507171387
142b03723d5
1519114b303
hexf527a207

4113015303 has 16 divisors (see below), whose sum is σ = 5740664832. Its totient is φ = 2616180000.

The previous prime is 4113015299. The next prime is 4113015311. The reversal of 4113015303 is 3035103114.

4113015303 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 4113015303 - 22 = 4113015299 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4113015303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4113015353) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 304848 + ... + 318053.

It is an arithmetic number, because the mean of its divisors is an integer number (358791552).

Almost surely, 24113015303 is an apocalyptic number.

4113015303 is a deficient number, since it is larger than the sum of its proper divisors (1627649529).

4113015303 is a wasteful number, since it uses less digits than its factorization.

4113015303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 623006.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 4113015303 is about 64132.7942865427. The cubic root of 4113015303 is about 1602.2124734354.

Adding to 4113015303 its reverse (3035103114), we get a palindrome (7148118417).

The spelling of 4113015303 in words is "four billion, one hundred thirteen million, fifteen thousand, three hundred three".

Divisors: 1 3 31 71 93 213 2201 6603 622901 1868703 19309931 44225971 57929793 132677913 1371005101 4113015303