4113111412021 has 4 divisors (see below), whose sum is σ = 4245792425344. Its totient is φ = 3980430398700.

The previous prime is 4113111412013. The next prime is 4113111412127. The reversal of 4113111412021 is 1202141113114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4113111412021 - 2³ = 4113111412013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4113111411983 and 4113111412001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4113111410021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66340506615 + ... + 66340506676.

It is an arithmetic number, because the mean of its divisors is an integer number (1061448106336).

Almost surely, 2^{4113111412021} is an apocalyptic number.

It is an amenable number.

4113111412021 is a deficient number, since it is larger than the sum of its proper divisors (132681013323).

4113111412021 is a wasteful number, since it uses less digits than its factorization.

4113111412021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132681013322.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 4113111412021 its reverse (1202141113114), we get a palindrome (5315252525135).

The spelling of 4113111412021 in words is "four trillion, one hundred thirteen billion, one hundred eleven million, four hundred twelve thousand, twenty-one".