4113111433 has 4 divisors (see below), whose sum is σ = 4113239760. Its totient is φ = 4112983108.

The previous prime is 4113111389. The next prime is 4113111473. The reversal of 4113111433 is 3341113114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3341113114 = 2 ⋅1670556557.

It is a cyclic number.

It is not a de Polignac number, because 4113111433 - 2⁹ = 4113110921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4113111473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29166 + ... + 95272.

It is an arithmetic number, because the mean of its divisors is an integer number (1028309940).

Almost surely, 2^4113111433 is an apocalyptic number.

It is an amenable number.

4113111433 is a deficient number, since it is larger than the sum of its proper divisors (128327).

4113111433 is an equidigital number, since it uses as much as digits as its factorization.

4113111433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128326.

The product of its digits is 432, while the sum is 22.

The square root of 4113111433 is about 64133.5437427248. The cubic root of 4113111433 is about 1602.2249557202.

Adding to 4113111433 its reverse (3341113114), we get a palindrome (7454224547).

The spelling of 4113111433 in words is "four billion, one hundred thirteen million, one hundred eleven thousand, four hundred thirty-three".