Base | Representation |
---|---|
bin | 10010101101000101000100… |
… | …10101101010011101001101 |
3 | 12101122010011010200201220020 |
4 | 21112202202111222131031 |
5 | 20342343431041230123 |
6 | 223251250005212353 |
7 | 11443432465643241 |
oct | 1126424225523515 |
9 | 171563133621806 |
10 | 41131330414413 |
11 | 12118776800138 |
12 | 474363b4010b9 |
13 | 19c488b261595 |
14 | a22aa4988421 |
15 | 4b4dc0ee37e3 |
hex | 2568a256a74d |
41131330414413 has 4 divisors (see below), whose sum is σ = 54841773885888. Its totient is φ = 27420886942940.
The previous prime is 41131330414337. The next prime is 41131330414429. The reversal of 41131330414413 is 31441403313114.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41131330414413 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41131330414463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6855221735733 + ... + 6855221735738.
It is an arithmetic number, because the mean of its divisors is an integer number (13710443471472).
Almost surely, 241131330414413 is an apocalyptic number.
It is an amenable number.
41131330414413 is a deficient number, since it is larger than the sum of its proper divisors (13710443471475).
41131330414413 is a wasteful number, since it uses less digits than its factorization.
41131330414413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13710443471474.
The product of its (nonzero) digits is 20736, while the sum is 33.
Adding to 41131330414413 its reverse (31441403313114), we get a palindrome (72572733727527).
The spelling of 41131330414413 in words is "forty-one trillion, one hundred thirty-one billion, three hundred thirty million, four hundred fourteen thousand, four hundred thirteen".
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