411321241033 has 4 divisors (see below), whose sum is σ = 411331153860. Its totient is φ = 411311328208.

The previous prime is 411321241027. The next prime is 411321241039. The reversal of 411321241033 is 330142123114.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (411321241027) and next prime (411321241039).

It can be written as a sum of positive squares in 2 ways, for example, as 51269639184 + 360051601849 = 226428^2 + 600043^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-411321241033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411321240989 and 411321241007.

It is not an unprimeable number, because it can be changed into a prime (411321241039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4893910 + ... + 4977247.

It is an arithmetic number, because the mean of its divisors is an integer number (102832788465).

Almost surely, 2^411321241033 is an apocalyptic number.

It is an amenable number.

411321241033 is a deficient number, since it is larger than the sum of its proper divisors (9912827).

411321241033 is an equidigital number, since it uses as much as digits as its factorization.

411321241033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9912826.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 411321241033 its reverse (330142123114), we get a palindrome (741463364147).

The spelling of 411321241033 in words is "four hundred eleven billion, three hundred twenty-one million, two hundred forty-one thousand, thirty-three".