Base | Representation |
---|---|
bin | 111011110110101111110… |
… | …111010001001000000101 |
3 | 112120012222100211012221202 |
4 | 323312233313101020011 |
5 | 1014342400424000031 |
6 | 12425332123552245 |
7 | 603112530566210 |
oct | 73665767211005 |
9 | 15505870735852 |
10 | 4113234203141 |
11 | 134645a526438 |
12 | 56520998b685 |
13 | 23ab5137b2bb |
14 | 10311dc92777 |
15 | 71edbeaa2cb |
hex | 3bdafdd1205 |
4113234203141 has 8 divisors (see below), whose sum is σ = 4703739064704. Its totient is φ = 3523454335440.
The previous prime is 4113234203131. The next prime is 4113234203201. The reversal of 4113234203141 is 1413024323114.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4113234203141 - 234 = 4096054333957 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113234203131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 181236305 + ... + 181258998.
It is an arithmetic number, because the mean of its divisors is an integer number (587967383088).
Almost surely, 24113234203141 is an apocalyptic number.
It is an amenable number.
4113234203141 is a deficient number, since it is larger than the sum of its proper divisors (590504861563).
4113234203141 is a wasteful number, since it uses less digits than its factorization.
4113234203141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 362496931.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 4113234203141 its reverse (1413024323114), we get a palindrome (5526258526255).
The spelling of 4113234203141 in words is "four trillion, one hundred thirteen billion, two hundred thirty-four million, two hundred three thousand, one hundred forty-one".
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