4113241214233 has 4 divisors (see below), whose sum is σ = 4113246274740. Its totient is φ = 4113236153728.

The previous prime is 4113241214209. The next prime is 4113241214273. The reversal of 4113241214233 is 3324121423114.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 2293189291584 + 1820051922649 = 1514328^2 + 1349093^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4113241214233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4113241214195 and 4113241214204.

It is not an unprimeable number, because it can be changed into a prime (4113241214273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1004260 + ... + 3038917.

It is an arithmetic number, because the mean of its divisors is an integer number (1028311568685).

Almost surely, 2^{4113241214233} is an apocalyptic number.

It is an amenable number.

4113241214233 is a deficient number, since it is larger than the sum of its proper divisors (5060507).

4113241214233 is a wasteful number, since it uses less digits than its factorization.

4113241214233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5060506.

The product of its digits is 13824, while the sum is 31.

Adding to 4113241214233 its reverse (3324121423114), we get a palindrome (7437362637347).

The spelling of 4113241214233 in words is "four trillion, one hundred thirteen billion, two hundred forty-one million, two hundred fourteen thousand, two hundred thirty-three".