Base | Representation |
---|---|
bin | 111011110110110000111… |
… | …100000000100100011111 |
3 | 112120020000121201201220200 |
4 | 323312300330000210133 |
5 | 1014342420032121023 |
6 | 12425334010114543 |
7 | 603113140011051 |
oct | 73666074004437 |
9 | 15506017651820 |
10 | 4113252223263 |
11 | 13464697141a7 |
12 | 565213a1ba53 |
13 | 23ab5501a4b1 |
14 | 1031224238d1 |
15 | 71edd869743 |
hex | 3bdb0f0091f |
4113252223263 has 12 divisors (see below), whose sum is σ = 5943066276888. Its totient is φ = 2741382631440.
The previous prime is 4113252223229. The next prime is 4113252223271. The reversal of 4113252223263 is 3623222523114.
4113252223263 is a `hidden beast` number, since 4 + 1 + 1 + 325 + 2 + 2 + 2 + 326 + 3 = 666.
It is not a de Polignac number, because 4113252223263 - 213 = 4113252215071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113252023263) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 65426620 + ... + 65489457.
It is an arithmetic number, because the mean of its divisors is an integer number (495255523074).
Almost surely, 24113252223263 is an apocalyptic number.
4113252223263 is a deficient number, since it is larger than the sum of its proper divisors (1829814053625).
4113252223263 is a wasteful number, since it uses less digits than its factorization.
4113252223263 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130919574 (or 130919571 counting only the distinct ones).
The product of its digits is 103680, while the sum is 36.
Adding to 4113252223263 its reverse (3623222523114), we get a palindrome (7736474746377).
The spelling of 4113252223263 in words is "four trillion, one hundred thirteen billion, two hundred fifty-two million, two hundred twenty-three thousand, two hundred sixty-three".
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