411330200000111 has 4 divisors (see below), whose sum is σ = 470091657142992. Its totient is φ = 352568742857232.

The previous prime is 411330200000099. The next prime is 411330200000113. The reversal of 411330200000111 is 111000002033114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 411330200000111 - 2²² = 411330195805807 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 411330200000111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411330200000113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29380728571430 + ... + 29380728571443.

It is an arithmetic number, because the mean of its divisors is an integer number (117522914285748).

Almost surely, 2^{411330200000111} is an apocalyptic number.

411330200000111 is a deficient number, since it is larger than the sum of its proper divisors (58761457142881).

411330200000111 is an equidigital number, since it uses as much as digits as its factorization.

411330200000111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58761457142880.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 411330200000111 its reverse (111000002033114), we get a palindrome (522330202033225).

The spelling of 411330200000111 in words is "four hundred eleven trillion, three hundred thirty billion, two hundred million, one hundred eleven", and thus it is an aban number.