Base | Representation |
---|---|
bin | 111011110110110011111… |
… | …111010100110010001101 |
3 | 112120020011012002000022111 |
4 | 323312303333110302031 |
5 | 1014343021134033031 |
6 | 12425343035344021 |
7 | 603114331136542 |
oct | 73666377246215 |
9 | 15506135060274 |
10 | 4113303424141 |
11 | 134649560517a |
12 | 565228bb2011 |
13 | 23ab62806382 |
14 | 103129150bc9 |
15 | 71ee30d01b1 |
hex | 3bdb3fd4c8d |
4113303424141 has 4 divisors (see below), whose sum is σ = 4115928380032. Its totient is φ = 4110678468252.
The previous prime is 4113303424121. The next prime is 4113303424163. The reversal of 4113303424141 is 1414243033114.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4113303424141 - 223 = 4113295035533 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113303424121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312475595 + ... + 1312478728.
It is an arithmetic number, because the mean of its divisors is an integer number (1028982095008).
Almost surely, 24113303424141 is an apocalyptic number.
It is an amenable number.
4113303424141 is a deficient number, since it is larger than the sum of its proper divisors (2624955891).
4113303424141 is a wasteful number, since it uses less digits than its factorization.
4113303424141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2624955890.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 4113303424141 its reverse (1414243033114), we get a palindrome (5527546457255).
The spelling of 4113303424141 in words is "four trillion, one hundred thirteen billion, three hundred three million, four hundred twenty-four thousand, one hundred forty-one".
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