41133332513513 has 4 divisors (see below), whose sum is σ = 41138928131328. Its totient is φ = 41127736895700.

The previous prime is 41133332513489. The next prime is 41133332513519. The reversal of 41133332513513 is 31531523333114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41133332513513 - 2²⁴ = 41133315736297 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41133332513519) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2797797881 + ... + 2797812582.

It is an arithmetic number, because the mean of its divisors is an integer number (10284732032832).

Almost surely, 2^{41133332513513} is an apocalyptic number.

It is an amenable number.

41133332513513 is a deficient number, since it is larger than the sum of its proper divisors (5595617815).

41133332513513 is an equidigital number, since it uses as much as digits as its factorization.

41133332513513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5595617814.

The product of its digits is 145800, while the sum is 38.

Adding to 41133332513513 its reverse (31531523333114), we get a palindrome (72664855846627).

The spelling of 41133332513513 in words is "forty-one trillion, one hundred thirty-three billion, three hundred thirty-two million, five hundred thirteen thousand, five hundred thirteen".