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41133334020203 = 97424054989899
BaseRepresentation
bin10010101101001000110011…
…10000110100000001101011
312101122022022202211110100002
421112210121300310001223
520342412032002121303
6223252220501333215
711443533235213445
oct1126443160640153
9171568282743302
1041133334020203
111211960478a897
124743aba40720b
1319c4b1a39bc39
14a22c14b01495
154b4e8bd69788
hex256919c3406b

41133334020203 has 4 divisors (see below), whose sum is σ = 41557389010200. Its totient is φ = 40709279030208.

The previous prime is 41133334020157. The next prime is 41133334020227. The reversal of 41133334020203 is 30202043333114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41133334020203 - 212 = 41133334016107 is a prime.

It is a super-2 number, since 2×411333340202032 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41133334020703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212027494853 + ... + 212027495046.

It is an arithmetic number, because the mean of its divisors is an integer number (10389347252550).

Almost surely, 241133334020203 is an apocalyptic number.

41133334020203 is a deficient number, since it is larger than the sum of its proper divisors (424054989997).

41133334020203 is an equidigital number, since it uses as much as digits as its factorization.

41133334020203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 424054989996.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 41133334020203 its reverse (30202043333114), we get a palindrome (71335377353317).

The spelling of 41133334020203 in words is "forty-one trillion, one hundred thirty-three billion, three hundred thirty-four million, twenty thousand, two hundred three".

Divisors: 1 97 424054989899 41133334020203