41133351411313 has 4 divisors (see below), whose sum is σ = 47009544470080. Its totient is φ = 35257158352548.

The previous prime is 41133351411307. The next prime is 41133351411329. The reversal of 41133351411313 is 31311415333114.

41133351411313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41133351411313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41133351511313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2938096529373 + ... + 2938096529386.

It is an arithmetic number, because the mean of its divisors is an integer number (11752386117520).

Almost surely, 2^{41133351411313} is an apocalyptic number.

It is an amenable number.

41133351411313 is a deficient number, since it is larger than the sum of its proper divisors (5876193058767).

41133351411313 is an equidigital number, since it uses as much as digits as its factorization.

41133351411313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5876193058766.

The product of its digits is 19440, while the sum is 34.

Adding to 41133351411313 its reverse (31311415333114), we get a palindrome (72444766744427).

The spelling of 41133351411313 in words is "forty-one trillion, one hundred thirty-three billion, three hundred fifty-one million, four hundred eleven thousand, three hundred thirteen".