Base | Representation |
---|---|
bin | 111011110110110110011… |
… | …011101110011000001001 |
3 | 112120020021001012222202210 |
4 | 323312312123232120021 |
5 | 1014343112133022213 |
6 | 12425351102215333 |
7 | 603115336466160 |
oct | 73666633563011 |
9 | 15506231188683 |
10 | 4113344423433 |
11 | 1346506768593 |
12 | 56523a884549 |
13 | 23ab6b15c9cb |
14 | 1031307843d7 |
15 | 71ee69cd0c3 |
hex | 3bdb66ee609 |
4113344423433 has 32 divisors (see below), whose sum is σ = 6484572610560. Its totient is φ = 2269262399040.
The previous prime is 4113344423329. The next prime is 4113344423437. The reversal of 4113344423433 is 3343244433114.
It is not a de Polignac number, because 4113344423433 - 29 = 4113344422921 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 4113344423391 and 4113344423400.
It is not an unprimeable number, because it can be changed into a prime (4113344423437) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8163868 + ... + 8653058.
It is an arithmetic number, because the mean of its divisors is an integer number (202642894080).
Almost surely, 24113344423433 is an apocalyptic number.
It is an amenable number.
4113344423433 is a deficient number, since it is larger than the sum of its proper divisors (2371228187127).
4113344423433 is a wasteful number, since it uses less digits than its factorization.
4113344423433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 503037.
The product of its digits is 497664, while the sum is 39.
Adding to 4113344423433 its reverse (3343244433114), we get a palindrome (7456588856547).
The spelling of 4113344423433 in words is "four trillion, one hundred thirteen billion, three hundred forty-four million, four hundred twenty-three thousand, four hundred thirty-three".
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