411343244051 has 4 divisors (see below), whose sum is σ = 411344534832. Its totient is φ = 411341953272.

The previous prime is 411343244023. The next prime is 411343244119. The reversal of 411343244051 is 150442343114.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-411343244051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411343243999 and 411343244017.

It is not an unprimeable number, because it can be changed into a prime (411393244051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214685 + ... + 932081.

It is an arithmetic number, because the mean of its divisors is an integer number (102836133708).

Almost surely, 2^411343244051 is an apocalyptic number.

411343244051 is a deficient number, since it is larger than the sum of its proper divisors (1290781).

411343244051 is an equidigital number, since it uses as much as digits as its factorization.

411343244051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1290780.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 411343244051 its reverse (150442343114), we get a palindrome (561785587165).

The spelling of 411343244051 in words is "four hundred eleven billion, three hundred forty-three million, two hundred forty-four thousand, fifty-one".