41135035454341 has 4 divisors (see below), whose sum is σ = 41135132248000. Its totient is φ = 41134938660684.

The previous prime is 41135035454333. The next prime is 41135035454363. The reversal of 41135035454341 is 14345453053114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41135035454341 - 2³ = 41135035454333 is a prime.

It is a super-3 number, since 3×41135035454341³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41135035454321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47756541 + ... + 48610258.

It is an arithmetic number, because the mean of its divisors is an integer number (10283783062000).

Almost surely, 2^{41135035454341} is an apocalyptic number.

It is an amenable number.

41135035454341 is a deficient number, since it is larger than the sum of its proper divisors (96793659).

41135035454341 is an equidigital number, since it uses as much as digits as its factorization.

41135035454341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96793658.

The product of its (nonzero) digits is 864000, while the sum is 43.

The spelling of 41135035454341 in words is "forty-one trillion, one hundred thirty-five billion, thirty-five million, four hundred fifty-four thousand, three hundred forty-one".