411401130313441 has 4 divisors (see below), whose sum is σ = 411406186263984. Its totient is φ = 411396074362900.

The previous prime is 411401130313417. The next prime is 411401130313477. The reversal of 411401130313441 is 144313031104114.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411401130313441 - 2³³ = 411392540378849 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (411401130353441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2527853215 + ... + 2528015956.

It is an arithmetic number, because the mean of its divisors is an integer number (102851546565996).

Almost surely, 2^{411401130313441} is an apocalyptic number.

It is an amenable number.

411401130313441 is a deficient number, since it is larger than the sum of its proper divisors (5055950543).

411401130313441 is an equidigital number, since it uses as much as digits as its factorization.

411401130313441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5055950542.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 411401130313441 its reverse (144313031104114), we get a palindrome (555714161417555).

The spelling of 411401130313441 in words is "four hundred eleven trillion, four hundred one billion, one hundred thirty million, three hundred thirteen thousand, four hundred forty-one".