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4114020443011 = 37111189741703
BaseRepresentation
bin111011110111011110101…
…110100010001110000011
3112120022000011021100021221
4323313132232202032003
51014401003213134021
612425542131455511
7603141155532553
oct73673656421603
915508004240257
104114020443011
111346823319056
125653a9157597
1323ac48223cab
14103196479163
1572036015241
hex3bddeba2383

4114020443011 has 4 divisors (see below), whose sum is σ = 4225210184752. Its totient is φ = 4002830701272.

The previous prime is 4114020442969. The next prime is 4114020443059. The reversal of 4114020443011 is 1103440204114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4114020443011 - 211 = 4114020440963 is a prime.

It is a super-2 number, since 2×41140204430112 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4114020443711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55594870815 + ... + 55594870888.

It is an arithmetic number, because the mean of its divisors is an integer number (1056302546188).

Almost surely, 24114020443011 is an apocalyptic number.

4114020443011 is a deficient number, since it is larger than the sum of its proper divisors (111189741741).

4114020443011 is a wasteful number, since it uses less digits than its factorization.

4114020443011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111189741740.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 4114020443011 its reverse (1103440204114), we get a palindrome (5217460647125).

The spelling of 4114020443011 in words is "four trillion, one hundred fourteen billion, twenty million, four hundred forty-three thousand, eleven".

Divisors: 1 37 111189741703 4114020443011