4114121400343 has 4 divisors (see below), whose sum is σ = 4114831839808. Its totient is φ = 4113410960880.

The previous prime is 4114121400341. The next prime is 4114121400401. The reversal of 4114121400343 is 3430041214114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4114121400343 - 2¹ = 4114121400341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4114121400341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355211046 + ... + 355222627.

It is an arithmetic number, because the mean of its divisors is an integer number (1028707959952).

Almost surely, 2^{4114121400343} is an apocalyptic number.

4114121400343 is a deficient number, since it is larger than the sum of its proper divisors (710439465).

4114121400343 is an equidigital number, since it uses as much as digits as its factorization.

4114121400343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 710439464.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 4114121400343 its reverse (3430041214114), we get a palindrome (7544162614457).

The spelling of 4114121400343 in words is "four trillion, one hundred fourteen billion, one hundred twenty-one million, four hundred thousand, three hundred forty-three".