Search a number
-
+
41141333341 = 191215399651
BaseRepresentation
bin100110010100001101…
…101110110101011101
310221012012200021111201
4212110031232311131
51133224140131331
630522225315501
72654343364153
oct462415566535
9127165607451
1041141333341
11164a2234739
127b82195b91
133b58675934
141dc3dc93d3
15110bcd4a61
hex99436ed5d

41141333341 has 4 divisors (see below), whose sum is σ = 41356733184. Its totient is φ = 40925933500.

The previous prime is 41141333297. The next prime is 41141333347. The reversal of 41141333341 is 14333314114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41141333341 - 217 = 41141202269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41141333347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107699635 + ... + 107700016.

It is an arithmetic number, because the mean of its divisors is an integer number (10339183296).

Almost surely, 241141333341 is an apocalyptic number.

It is an amenable number.

41141333341 is a deficient number, since it is larger than the sum of its proper divisors (215399843).

41141333341 is a wasteful number, since it uses less digits than its factorization.

41141333341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215399842.

The product of its digits is 5184, while the sum is 28.

Adding to 41141333341 its reverse (14333314114), we get a palindrome (55474647455).

The spelling of 41141333341 in words is "forty-one billion, one hundred forty-one million, three hundred thirty-three thousand, three hundred forty-one".

Divisors: 1 191 215399651 41141333341